how many whole numbers lie between the squares of n and (n+1) ?
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Number lying between the square of (X + 1) and ( X + 2 ).
= ( X + 2)² - ( X + 1)² - 1
using a² - b² = (a + b)(a - b)
a = ( X + 2)
b = ( X + 1)
= (X + 2 + X + 1)( X + 2 - (X + 1)) - 1
= (2X + 3)(1) - 1
= 2X + 3 - 1
= 2X + 2
= 2(X + 1)
Step-by-step explanation:
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