Question

How many
whose each
3.
bides daw a regular palygon whos
Anterior angle is 150'.​

Answer 1

Answer:

Regular polygon with interior angle = 156 deg.

It has each exterior angle = 180–156 = 24 deg.

No. of sides in regular polygon = 360/24 = 15.

No. of vertices = 15.

Sum of the interior angles = (15–2)*180 = 13*180 = 2340 deg.

No. of diagonals = 15*(15–3)/2 = 15*6 = 90.

No. of triangles = 13.

No. of isosceles triangles = 15.

Diameter of inscribed circle = s*cot (180/15) = 4.704630109 s, (where s is the side)

Diameter of circumscribed circle = s*cosec (180/15) = 4.809734345 s,

Explanation:

Mark me as brainlist please