Question

how many will be needed to a cover a rectangular floor of length 24 M and breadth 18 M if each tile is of length 2 cm breadth 1 metre

Answer 1

Length of floor = 24m

Breadth of floor=18m

Length of each tile= 2m

&breadth of each tile= 1m

No. Of tiles = area of a rectangular floor/ area of each tile

= 24*18/2*1

=216

Hope it helps you

Answer 2

$<b>Hi !$

Here is your answer !!

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Length of the floor = 24 m

Breadth of the floor = 18 m

Area = Length × Breadth

A = 24 × 18 = 432 m²

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Length of the tile = 2 m

Breadth of the tile = 1 m

Area = 2 × 1 = 2 m²

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Therefore , number of tiles needed to cover the floor = ?

$= > \bf \: \frac{area \: of \: floor}{area \: of \: one \: tile} \\ \\ = > \bf \: \frac{432}{2} \\ \\ = > \bf \: 216 \: tiles$

$<u>ANS ) 216 tiles are needed to cover the floor.$

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Thanks !!