Question

how many words can be form from word parallel
no L will comes together

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Answer 1

ᴇʟʟᴏ ᴍᴀᴛᴇ ✋

According to the problem, the totaʟ number of L's are 3 and A's are 2.

The possible arrangements are

= 2×38 = 3360

we consider 2 L's as a single letter ,

therefore total numbers are 6 having 2 A's. So,

Number of possible arrangements are = 26 = 360

Hence the number of arrangements without L's together are = 3360−360 = 3000

sᴛᴀʏ sᴀғᴇ ❤️

ᴋʀɪᴛɪ ʜᴇʀᴇ

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Answer 2

Calculation:

Number of words that can be formed with letters of 'parallel' = 8! / (2!3!)

= 3360

Consider all three I's as a single letter. So we have 6 letters i.e. P , A , R , A , E , LLL

Number of words with all I's together = 6!/2!

= 360

Number of arrangements with all I's

together = 3360 - 360

= 3000

3000 words can be fromed so that all I's does not come together.