Math, asked by skbarua2015, 1 year ago

How many words can be formed by the letters of the word TRAPEZIUM selecting 2 vowels and 3 consonants so that no letter is repeated in any word.

Answers

Answered by VEDULAKRISHNACHAITAN
14

Answer:

7200

Step-by-step explanation:

Hi,

In the given word  TRAPEZIUM , all the letters are distinct and in total there

are 4 vowels and 5 consonants in this word.

2 vowels out of 4 vowels can be selected in 4C2 ways.

3 consonant out of 5 consonants can be selected in 5C3 ways.

So, 2 vowels and 3 consonants can be selected in 4C2*5C3 ways

    = 6*10 = 60.

Total number of ways , in which we can select 2 vowels and 3 consonants

are 60

These selected 5 letters(2 vowels and 3 consonants) can be arranged

amongselves in 5! ways = 120

Hence total number of words that can be formed = 120*60 = 7200

Hope, it helped !

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