Question

How many words of seven letters can be formed by using the letters of the word ‘SUCCESS’ so that ...

(01) the two C’s are together but not the two S (02) neither the two C nor the two S are together​

Answer 1

Answer:

(01) 3!+3!

(02) (4!/2!)+{(4!/2!)-2}

Step-by-step explanation:

(01)

take the letters at either ODD positions or at EVEN positions i. e.,

S_S_S_

_S_S_S

and cosider both the C's as single letter.

so, 3 letters have to be arranged in the fillings which are also 3.

that results to 2(3!)

(02)

as similar to (01),S's

are placed initially at odd or even places

S_S_S_ _

_S_S_S_

and the total permutations are 2(4!)

now considering that a possibilty for the words SUSESCC, SESUSCC are in cluded in 2(4!) so subtract 2 from 2(4!)

results in 2(4!)2