Question

How many years will a sum of money double itself at 10%pa please​ full explanation please

Answer 1

Answer:

R100=10100=0.1

Thus, we have,

I=P×R×t100

Since, I = P (as calculated above), we have,

P = P×R×t100

We can cancel P from both sides. Thus, we have,

1=R×t100

Plugging in the known values, we have,

1= 0.1×t

Since, R100=0.1

Now,

t=10 years