how many years will it take for rupees 54000 to double at a simple interest rate of 8%?
answer should come 12.5 years..
Answers
Required answer:–
Given:–
• R = 8%
• P = Rs. 54000
To find:–
• Time (n) taken to double amount
Assumptions:–
• Let amount be 2P
Where,
• R = Rate
• P = Principal
• n = Time
Formulas used:–
• Amount = Principal×Rate×Time / 100 + P
Step by step explaination:–
Calculating the amount and putting values...
That is,
2P = (54000 × N × R) / 100+P
2P-P = 54000×N×8 / 100
P = 540 × N × 8
Now putting the value of Principal...
That is,
54000 = 540 × N × 8
N = 54000 / 540×8
N = 12.5
Answer:–
Time (years) taken is 12.5 years
Extra information:–
★ The money borrowed is called the Principal, the extra money paid for using lender's money is called the interest and the total money, paid to the lender at the end of the specified period is called the amount.
______________________________
Note: When we say, interest it always means Simple Interest.
Given
- Principal, P = Rs 54, 000
- Amount, A = Rs 1, 20, 000
- Rate of interest, R = 8 % per annum
- Let time taken be 'T' years.
We know,
Now,
Using formula of Simple interest, we have
where,
- P denotes Principal
- R denotes Rate
- T denotes Time
So,
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