Question

how many years will it take to double amount of rupee 1000 if the simple interest is 10%
plz help me ​

Answer 1

Answer:

It is given that,

Principle (P)=Rs 1000

Rate (R)=10%

Simple interest S.I=

100

PRT

S.I for 1 year =

100

1000×10×1

=100S.I for 2 year =

100

1000×10×2

=200S.I for 3 year =

100

1000×10×3

=300

Hence, the total interest amount is in A.P. i.e 100,200,300,..

Here,

a=100

d=100

Now,

a

n

=a+(n−1)d

a

20

=a+(20−1)d

=100+19(100)

=100+1900

2000

Hence, the interest amount after 20 years is Rs. 2000.

Answer 2

Answer:

100 year

Step-by-step explanation:

• Amonut = 1000
• Rate on amount per anumm = 10%
• according to question double amount of principal is amount
• And Intrest = 1000 rs

To Find = after how many year amount will be double

Solution:-

$time \: = \frac{si \times 100}{r \: \times t} \\ \frac{1000 \times 100}{10 \times 100} = \frac{100000}{1000} \\ 100 \: year$