Question

How many years would it take to spend avogadro's number of rupees at the rate of 10 lakh rupees per second?

Answer 1

Answer:

1.9 × 10^10

Step-by-step explanation:

A lakh equals 100,000 rupees? Is this right? Let's assume so.

So, 10 lakh = 100,000 x 10 = 1,000,000 rupees per second

So, to spend Avogadro Number of rupees at the rate of one million per second requires this:

6.022 x 10^23 rupee divided by 1 x 10^6 rupee/sec = 6.022 x 10^17 seconds

How many second in one year?

(365 da/yr) x (24 hr/da) x (3600 sec/hr) = 31536000 sec/yr

The answer is 1.9 x 10^10 years. That's a rather long time!

Hope it help you

Answer 2

$\sf \: 1 \: sec \: ⟶ \: 10 \: lakh$

$\sf \: 1 \: sec \: ⟶ \: 1000000$

$\sf \: 1 \: sec \: ⟶ \sf \: 1 {0}^{6}$

$\: ?\: ⟶ \sf\:6 \times {10}^{23}$

$\displaystyle \qquad \: \sf = \: \frac{6 \times {10}^{23} }{ {10}^{6} } \times 1 \: sec$

$\displaystyle \sf \qquad \: = \: \frac{6 \times {10}^{23} }{ {10}^{6} } \times \frac{1}{365 \times 24 \times 60 \times 60} yrs$

$\displaystyle \sf \qquad \: = \: \frac{ \cancel6 \times {10}^{15} }{ {365 \times 24 \times \cancel{36}}}$

$\displaystyle \sf \qquad \: = \: \frac{{10}^{15} }{ {365 \times 24 \times 6}}$

$\displaystyle \sf \qquad \: = \: \frac{{10}^{15} }{ {52560}}$

$\displaystyle \sf \qquad \: = \: \frac{1 }{ {52560}} \times {10}^{14}$

$\displaystyle \sf \qquad \: = \: \frac{10000 }{ {52560}} \times {10}^{10}$

$\displaystyle \bf \qquad \: = \: 1.902 \times {10}^{10}$

$\:$

NOTE :

$\qquad\sf1 \: year = 365×24×60×60 \\ \\ \sf \qquad 1 \: sec = \frac{1}{365×24×60×60 } \: yrs$