Question

How many zero(es) does the polynomial 293x2 - 293x have?

Answer 1

Answer:

It has 2 zeroes

Step-by-step explanation:

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Answer 2

The polynomial 293x² - 293x has two zeroes

Given : The polynomial 293x² - 293x

To find : The number of zeroes

Solution :

Step 1 of 3 :

Write down the given polynomial

The given polynomial is 293x² - 293x

Step 2 of 3 :

Find the zeroes of the polynomial

For Zeroes of the polynomial we have

293x² - 293x = 0

⇒ 293(x² - x) = 0

⇒ x² - x = 0

⇒ x( x - 1 ) = 0

Either x = 0 or x - 1 = 0

Again x - 1 = 0 gives x = 1

So the zeroes are 0 , 1

Step 3 of 3 :

Find the number of zeroes

Since the zeroes are 0 and 1

So the number of zeroes are two

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