How many zeroe of the polynomial 2x²-3x-4
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Answer: 2 zeroes
Step-by-step explanation:
1) First calculate the discriminant (usually denoted by 'd') using the formula d=b^2-4*a*c for polynomial ax^2+bx+c.
2) For the given polynomial,by comparing the values for a,b and c,we get;
a = 2, b= -3 , c= -4
3) Hence, d= (-3)^2 - 4*(2)*(-4) , d=41
Now(and always),
if d<0, the number of zeroes of the polynomial= 0
if d=0, the number of zeroes of the polynomial= 1
if d>0(our case), the number of zeroes of the polynomial= 2...
4) Hence,the total number of zeroes of the given polynomial =2..
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