How many zeroes are possible for the following curves (i) x3 -1 (ii) x2 =7x+12
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Question - How many zeroes are possible for the following curves (i) x3 -1 (ii) x2 =7x+12
Answer -
THERE IS A CONCEPT TO FIND NO OF ZEROES
THE NUMBER ON CUTS ON X AXIS IS THE NUMBER OF ZEROES
OR
HIGHEST DEGREE = NUMBER OF ZEROES
SO IN FIRST ITS 3 THERFORE THE NUMBER OF ZEROES =3
IN SECOND IT'S 2 THEREFORE 2 ZEROES
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Answered by
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Answer:
Step-by-step explanation:
1)x^3-1=0
X=1
1^3-1=0
One zero is possible
2)x^2+7x+12=0
X^2+4x+3x+12=0
X(x+4)+3(x+4)=0
X+4=0 or x+3=0
X=-4 or x-3
Zeroes are -4,-3 and also -6,-1
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