Question

How many zeroes would be there at the end of 11^(5!)!−1?

Answer 1

Step-by-step explanation:

Hello mate

Here is your answer

11^(5*4*3*2*1)!-1

= 11^(120)-1

Let apply assumptions on the last digit of power of 11

then we have

11^0= 1

11^1= 11

11^2= 121

11^3=1331

By observation we conclude that every power of 11 end with 1

So by subtracting 1 from the require power of 11 we get only 1 (0)

So the answer is 1

hope it helps

mark it as a brainlist and follow me too