Question

How many zeros dose the polynomial (x-3)²-4 can have? also, find it's zeros​.

Answer 1

Answer:

2 zero's maRk aS brAinlist questions plZ...

Answer 2

Answer:

1 and 5

Explanation:

{(x - 3)}^{2} - 4 \\ {x}^{2} - 6x + 9 - 4 \\ {x}^{2} - 6x + 5

Since, it is a quadratic polynomial it will have two zeroes.

Lets find the zeroes by quadratic equation.

x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{ -( - 6)± \sqrt{ {( - 6)}^{2} - 4(1)(5)} }{2(1)} \\ \\ x = \frac{6± \sqrt{36 - 20} }{2} \\ \\ x = \frac{6± \sqrt{16} }{2} \\ \\ x = \frac{6±4}{2} \\ \\ x = 5 \: or \: x = 1

Hence,the zeroes of the polynomial is 5 and 1.