How manygrams of neon will have the same number of atoms as 4 grams of calcium
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Answered by
0
Calcium :
A = 40
thus no of moles = 4 /40 = 0.1 moles = 6.022 * 10^22 atoms
Now
6.022 * 10^22 = 0.1 mole
Thus 0.1 = weight of the neon/10
thus weight of neon which will have the same number of atoms as 4 grams of calcium would have is 1 gram.
A = 40
thus no of moles = 4 /40 = 0.1 moles = 6.022 * 10^22 atoms
Now
6.022 * 10^22 = 0.1 mole
Thus 0.1 = weight of the neon/10
thus weight of neon which will have the same number of atoms as 4 grams of calcium would have is 1 gram.
Answered by
1
Number of particles in 4 g of Ca,
= 4/40×6.022×10²³
= 6.022×10²² atoms
Therefore, number of atoms of Ne same as 4 g of Ca
= 20×6.022×10²²/6.022×10²³
=20/10
=2 g
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