Question

How maximum height of buikding is found by elastic behaviour of materials?

Answer 1

• he maximum height of mountain on earth depends upon shear modulus of rock. At the

base of the mountain, the stress due to all the rock on the top should be less than the

critical shear stress at which the rock begins to flow. Suppose the height of the mountain

is h and the density of its rock is ρ . Then force per unit area (due to the weight of the

mountain) at the base = hρ g

The material at the experience this force per unit area in the vertical direction, but sides

of the mountain area free. Hence there is a tangential shear of the order of hρ g . The

elastic limit for a typical rock is about 3 ×108 Nm −2 and its density is 3 ×103 kgm −3

Hence hmax ρ g = 3 ×108

Or hmax

3 × 108

3 × 108

=

=

= 10, 000m = 10km

ρg

3 × 103 × 9.8

This is more than the height of the Mount Everest.

he maximum height of mountain on earth depends upon shear modulus of rock. At the

base of the mountain, the stress due to all the rock on the top should be less than the

critical shear stress at which the rock begins to flow. Suppose the height of the mountain

is h and the density of its rock is ρ . Then force per unit area (due to the weight of the

mountain) at the base = hρ g

The material at the experience this force per unit area in the vertical direction, but sides

of the mountain area free. Hence there is a tangential shear of the order of hρ g . The

elastic limit for a typical rock is about 3 ×108 Nm −2 and its density is 3 ×103 kgm −3

Hence hmax ρ g = 3 ×108

Or hmax

3 × 108

3 × 108

=

=

= 10, 000m = 10km

ρg

3 × 103 × 9.8

This is more than the height of the Mount Everest.

• The maximum height of mountain on earth depends upon shear modulus of rock. At thebase of the mountain, the stress due to all the rock on the top should be less than thecritical shear stress at which ...
• The maximum height of mountain on earth depends upon shear modulus of rock. At thebase of the mountain, the stress due to all the rock on the top should be less than thecritical shear stress at which the rock begins to flow. Suppose the height of the mountainis h and the density of its rock is ρ . Then force per unit area (due to the weight of themountain) at the base = hρ gThe material at the experience this force per unit area in the vertical direction, but sidesof the mountain area free. Hence there is a tangential shear of the order of hρ g . Theelastic limit for a typical rock is about 3 ×108 Nm −2 and its density is 3 ×103 kgm −3Hence hmax ρ g = 3 ×108Or hmax3 × 1083 × 108=== 10, 000m = 10kmρg3 × 103 × 9.8This is more than the height of the Mount Everest.
• 3 years ago  
• Surendra
• 54 Points
• The maximum height of mountain on earth depends upon shear modulus of rock. At thebase of the mountain, the stress due to all the rock on the top should be less than thecritical shear stress at which the rock begins to flow. Suppose the height of the mountainis h and the density of its rock is ρ . Then force per unit area (due to the weight of themountain) at the base = hρ gThe material at the experience this force per unit area in the vertical direction, but sidesof the mountain area free. Hence there is a tangential shear of the order of hρ g . Theelastic limit for a typical rock is about 3 ×108 Nm −2 and its density is 3 ×103 kgm −3Hence hmax ρ g = 3 ×108Or hmax3 × 1083 × 108=== 10, 000m = 10kmρg3 × 103 × 9.8This is more than the height of the Mount Everest.