Question

how may minimum number of 2 Ohm resistance can be connected to have an effective resistance of 1.5 ohm​

Answer 1

4 resistances of value 2 ohms in parallel and one 2 ohms resistance in series.

Answer 2

Given that,

Resistance, R = 2 ohms

Effective resistance, $R_{eq}=1.5\ \Omega$

To find,

The minimum number of resistance.

Solution,

Let us connect 3 resistors of 2 ohms resistance in series such that the equivalent is given by :

R = 2 + 2 + 2

R=6 ohms

Now, if we connect 6 ohm and 2 ohm in parallel, then equivalent is given by :

$\dfrac{1}{R_e}=\dfrac{1}{6}+\dfrac{1}{2}\\\\R_2=1.5\ \Omega$

Hence, if we use 4 resistors of 2 ohm each, then the equivalent is equal to 1.5 ohms.

Learn more,

Equivalent Resistance

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