Question

How may this reaction be written in terms of the shapes of the reactants and product.
In this question, the methyl group, CH, is represented by Me.
Trimethylamine, Megn, reacts with boron trifluoride, BF3. to form a compound of formula
5
MezN.BF
Me
Me Me
"N
F
F
А
Me
Me Me
+
F-B
F-B
F
F
Me
Me-N
Me
B
Me
Me
B
ME
F
F
Me
Me. Me
F
Me
+
F-B
C
Me Me
B.
F
F
F
F
Me
Me TMe
Me
Me Me
+
D
N

Answer 1

I don't know dude this is very hard question sorry bro