Chemistry, asked by shreyashghodke8, 11 months ago

how methyl alcohol prepared from methyl iodide​

Answers

Answered by singhamanpratap0249
0

Answer:

Iodomethane can also be prepared by the reaction of methanol with aqueous hydrogen iodide: CH3OH + HI → CH3I + H2O. The generated iodomethane can be distilled from the reaction mixture. Iodomethane may also be prepared by treating iodoform with potassium hydroxide and dimethyl sulfate under 95% ethanol.

Answered by Anonymous
1

Alkyl iodides are prepared by heating alcohols with concentrated hydroiodic acid. Alkyl iodides can also be obtained by heating alcohols with sodium or potassium iodides in 95 % phosphoric acid.

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