how mich work is done when a force of 1 N moves of 1m in its own duration...
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Answered by
1
F= 1N
s=1m
work done=f×s
=1×1
= 1Joule
s=1m
work done=f×s
=1×1
= 1Joule
Answered by
0
Work done = Force multiply displacement
W= 1 Nmultiply 1m
W= 1 joule or m/s
W= 1 Nmultiply 1m
W= 1 joule or m/s
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