how mny natural number are there between 200 and 500 which are divisible by 7
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Answer:
First no. divisible by 7 b/w 200 and 500 = 203
Last no. divisible by 7 b/w 200 and 500 = 497
Difference between two consecutive terms (d) = 7
an = a + (n - 1)d
⇒ 497 = 203 + (n-1)7
⇒ 497 - 203 = 7n - 7
⇒ 294 + 7 = 7n
⇒ 301/7 =n
43 = n
43 numbers are divisible by 7 b/w 200-500.
Step-by-step explanation:
hence there are 43 number divisible by 7
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