Math, asked by srinivasdaroji, 7 months ago

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How
moing
terms of the AP:9, 17, 25,.
must be taken to given a sum of 636 ?

Answers

Answered by deepjashan9999
0

Answer:

Step-by-step explanation:

sn=n/2(2a+(n-1)d)

sn= 636 a=9 d=8

636=n/2(2*9+8n-8)

636*2=n(18+8n-8)

1272=10n+8n^2

8n^2+10n=1272

4n^2+5n=636

n=-5+- \sqrt{b^2-4ac/2a

=\sqrt{5^2-4*4*-636/2*4

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