how mole of oxygen atoms are there in 89.6 dm3 of SO2 at STP,???????
Answers
Answered by
1
Answer:
4O2 4mol o2 is needed
Explanation:
by pv=nrt
1dm3=1L
at stp pressure is 1atm , temperature is 273k
89.6×1=n×0.0821×273
89.6=22.4L×n
n=4 mol
s+o2 = so2
s+o2=4so2
4S+4o2=4SO2
so to make 4 mole SO2 we need 4mol o2
1molSO2 needs 1mol o2
Answered by
4
Answer:
22.4=89.6
2=X
So 2×89.6/22.4= 8
Similar questions