Chemistry, asked by rashmikamalshri, 1 year ago

How molecules of are present in 1 litre air containing 80% volume of at STP?

limzy: molecules of what?

rachana: ita air to it will be molecules of O2. At S.T.P., 1 mole of any gas = 22.4 Litres(It's a given. I assume you know thisone.) Therefore, 1 Litre of a gas = 1/22.4 = 0.0446 moles Out of these 0.0446 moles, 80% is Oxygen gas. Number of moles of Oxygen gas = 0.0446 x 80% = 0.0446x 80/100 = 0.0357 moles. 1 mole of any gas = 6.02 x 1023 units (This is also a given, known as the Avagadro's constant.) Therefore, 0.0357 moles = 0.0357 x 6.02 x 1023 = 2.15 x 1022 molecules of O2 is present in 1 litre air

Answers

Answered by prmkulk1978

207

The question should have been how many molecules of oxygen are present in 1 litre of air containing 80% of O2.
************************************************
Amount of oxygen present in 1 litre air is = 80% *1000 ml
= (80/100)*1000
=800ml
1 mole of any gas at STp, occupies 22.4 litre.
22400ml of O2 gas contains 6.022x 10^23 molecules.
1ml of O2 gas Contains =6.022x10^23/22400
800ml contains =(6.022x 10^23/22400) *800
=2.15 x 10^22 molecules.
Therefore, molecules present in 1 litre air containing 80% volume of at STP is 2.15x 10^22 moleculrs

Answered by princessbarbie01

127

✔Amount of oxygen in air is 1000 ml X 80% = 800 ml

At STP,
22400 ml O2 contains 6.022X10^23 molecules

1 ml O2 contains 6.022X10^23 / 22400 molecules
800 ml O2 contains (6.022X10^23/ 22400)X800 molecules = 2.15 X 10^22molecules

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