How much 0.068 M MgCl2 solution can be made by diluting 354 mL of 27.0 M MgCl2?
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this is done by using concept of dilution
it says that no of moles remains same before and after dilution.
therefore, M1V1= M2V2
27×354=0.068×V2
V2=27×354/0.068 ≈140.55 L
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