Question

how much 1M HCL should be mixed with what volume of 0.50M HCL in order to prepare 1L of 0.75M of HCL​

Answer 1

M1=1.0M,M2=0.25M

Let V1 and V2 are volumes required.

(1.0×V1+0.25×V2)=0.75(V1+V2)

⇒0.25V1=0.5V2,⇒V1:V2=2:1