how much 2x³-3x²+4x+5is greater than 2x³+7x²-2x+7?
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Answered by
5
it is greater than
-10x^2+6x -2
(2x^3 -3x^2+4x+5)- (2x^3+7x^2-2x+7)
2x^3-3x^2+4x+5-2x^3-7x^2+2x-7
-10x^2+6x-2
-10x^2+6x -2
(2x^3 -3x^2+4x+5)- (2x^3+7x^2-2x+7)
2x^3-3x^2+4x+5-2x^3-7x^2+2x-7
-10x^2+6x-2
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10x^2 this is 10x² correct this
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Answered by
4
Answer:
0-10x²+6-2
Step-by-step explanation:
(2x³-3x²+4x+5)-(2x³+7x²-2x+7)
2x³-3x²+4x+5-2x³-7x²+2x-7
2x³-2x³-3x²-7x²+4x+2x+5-7
0-10x²+6-2
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