Chemistry, asked by schumakera22, 11 months ago

How much 3.00 M CuSO4 is needed to prepare 25.00 mL of 0.100 M CuSO4?

Answers

Answered by ManthanShah

1

Answer: 0.833 ml

Explanation: You can simply use the formula, M1V1=M2V2

=> 3×x=0.1×25

=> x=0.83 ml

Hope ur answer is cleared. And if u r satisfied with the answer mark me as brainliest.

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