Question

how much a body of weight 35 Newton will wait in water. if it displays one litre of water?​

Answer 1

$\boxed{SOLUTION \: by \: RKRAUSHAN}$



Buoyant force acting on an object = weight of liquid displayed by that object.


mass of water displayed is 1 litre ,

F= M×g

Force/ weight= 10 Newtons.


Net weight become = 35-10 newton=25 newtons.


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