how much acetic acid should be weigh to make solution if we have 0.2 M Acetic acid of 500 ml
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Answer:
We know,
Number of moles/ Volume(in l) = Molarity
Volume =500ml or 0.5 l.
Number of moles= Molarity× Volume = 0.2× 0.5= 0.1 moles.
Molar mass of CH3COOH= 60g.
Weight of acetic acid= Molar mass × No: of moles
= 60×0.1= 6g.
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