Chemistry, asked by CrispyTekker7438, 11 months ago

How much acid should be added to 400ml of 15 acid solution to increase its strength to 32?

Answers

Answered by lakshmi62
8

What do we know:

400 ml is the total amount of solution right now

15% Acid means 60ml of the solution

400*.15 = 60 ml acid

400*.85 = 340 ml of non acidic fluid

then we can solve this by a ratio:

340/x = 0.68/0.32

solve for x = 160 ml of total acid

to find out how much needs to be added to the solution subtract the previous amount of acid 60ml

therefore 160ml - 60ml = 100 ml is the amount needed acid to be added.

if you need a single equation to be formulated we can work on this.

hope this helps :-)

Answered by nilesh102
6

Hi mate,

Solution :

=> Volume of alcohol in 400 ml solution

➾ 0.15 × 400 ml

=> Volume of alcohol in 400 ml solution

➾ 60 ml

=> Volume of others liquid

➾ 340 ml

=> Let x ml of alcohol is added to make it 32% strong

=> Then, volume of alcohol

➾ 60+x ml

=> Volume of other liquid

➾ 340 ml

=> Volume of solution

➾ 400 + x ml

➾ 0.32 × (400 + x) = 60 + x

➾ 128 + 0.32x = 60 + x

➾ 0.68x = 68

➾ 68x = 6800

➾ x = 100 ml ...

Answer : 100 ml pure alcohol must be added to 400ml of a 15% solution to make it's strength 32%

i hope it helps you

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