How much acid should be added to 400ml of 15 acid solution to increase its strength to 32?
Answers
What do we know:
400 ml is the total amount of solution right now
15% Acid means 60ml of the solution
400*.15 = 60 ml acid
400*.85 = 340 ml of non acidic fluid
then we can solve this by a ratio:
340/x = 0.68/0.32
solve for x = 160 ml of total acid
to find out how much needs to be added to the solution subtract the previous amount of acid 60ml
therefore 160ml - 60ml = 100 ml is the amount needed acid to be added.
if you need a single equation to be formulated we can work on this.
hope this helps :-)
Hi mate,
Solution :
=> Volume of alcohol in 400 ml solution
➾ 0.15 × 400 ml
=> Volume of alcohol in 400 ml solution
➾ 60 ml
=> Volume of others liquid
➾ 340 ml
=> Let x ml of alcohol is added to make it 32% strong
=> Then, volume of alcohol
➾ 60+x ml
=> Volume of other liquid
➾ 340 ml
=> Volume of solution
➾ 400 + x ml
➾ 0.32 × (400 + x) = 60 + x
➾ 128 + 0.32x = 60 + x
➾ 0.68x = 68
➾ 68x = 6800
➾ x = 100 ml ...
Answer : 100 ml pure alcohol must be added to 400ml of a 15% solution to make it's strength 32%
i hope it helps you