how much aluminium sheet will be required to make a container with lead who's length is 13 m breath is 8 metre and height is 4 m
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In this case we must find the TSA of the object to cover it with aluminium .
TSA of cuboid = 2(lb + bh + lh)
Given h = 4m
l = 13m
and b = 8m
TSA = 2(4*13 + 13*8 + 8*4 )
TSA = 2(188)
TSA = 376 square meters
Hence 376 square meters of aluminium sheets is required.
HOPE IT HELPS YOU !
CHEERS AND ALL THE BEST!
TSA of cuboid = 2(lb + bh + lh)
Given h = 4m
l = 13m
and b = 8m
TSA = 2(4*13 + 13*8 + 8*4 )
TSA = 2(188)
TSA = 376 square meters
Hence 376 square meters of aluminium sheets is required.
HOPE IT HELPS YOU !
CHEERS AND ALL THE BEST!
KalpeshJain:
the body also contains lid... and in ur calculations the area of that lid and bottom is not added... u just calculated side area... which is wrong acc. to question
thank you for correcting my mistake .
its ok...
Answered by
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This given body is a cuboidal in shape...
1) Area of surface with dimensions 13m & 4m= 13 × 4=52m^2
2) Area of surface with dimensions 4m & 8m=
4×8=32m^2
3)Area of top surface (lid) =13×8=104m^2
So..this is area of only 3 surfaces out of 6...and as the body is cuboidal...
TOTAL AREA=2×52+2×32+2×104=376m^2
So aluminum sheet of area 376m^2 is required.
1) Area of surface with dimensions 13m & 4m= 13 × 4=52m^2
2) Area of surface with dimensions 4m & 8m=
4×8=32m^2
3)Area of top surface (lid) =13×8=104m^2
So..this is area of only 3 surfaces out of 6...and as the body is cuboidal...
TOTAL AREA=2×52+2×32+2×104=376m^2
So aluminum sheet of area 376m^2 is required.
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