Question

How much ammonia will form when 28 g of nitrogen is mixed with 12 g of hydrogen.

Answer 1

Answer: 6 moles i.e., 102 grams of NH₃ is formed

Explanation:

The equation=

N₂ + 3H₂ ⇄ 2NH₃

1 mole N₂ = 14 grams of N₂

Given grams of N₂ = 28 = 2 moles

1 mole H₂ = 1 gram of H₂

Given grams of H₂ = 12 = 12 moles

Here nitrogen is the limiting agent

According to the equation

1 mole of N₂ will give 3 moles of NH₃

=> 2 moles of N₂ will give 3*2 = 6 moles of NH₃ = 6 * (14 +3) = 6 * 17 = 102 grams

Therefore 6 moles i.e., 102 grams of NH₃ is formed

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