Question

How much amount of Ammonium chloride is required to prepare it 15% solution in 100 g water?​

Answer 1

Answer:

Let the mass of sodium sulphate required to prepare the solution be "x" grams.

Mass of the solvent (water) is given as 100 g.

The mass of the solution would be (x +100) g

x g of solute (sodium sulphate) is dissolved in (x + 100) g of solution

or x = 25 g

25 g of sodium sulphate will be required to prepare its 20% solution in 100 g of water

Step-by-step explanation:

Mass of the solution = mass of solute + mass of solvent

Given that the mass percent of sodium sulphate solution is 20%.

Let the mass of sodium sulphate which is required to prepare this solution be x grams.

Given that the mass of water is 100 g.

So,

20 = [x/(x + 100)] * 100

20/100 = [x/x + 100]

1/5 = x/x + 100

x + 100/5 = x

x + 100 = 5x

5x - x = 100

4x = 100

x = 100/4

x = 25

Thus, 25g of sodium sulphate is required.

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Answer 2

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