Question

How much amount of ammonium nitrite has to be heated to produce 8.6g of N2 ? please solve...​

Answer 1

Answer:

$NH_{4} NO_{3}$ →$N_{2}O + 2H_{2}O$

⇒moles of $N_{2}$ in $N_{2}O$= moles of $N_{2}O$

⇒moles of $N_{2}O$= $\frac{8.6}{28}$

From the equation, we know

1 mole of $N_{2}O$= 1  mole of $NH_{4} NO_{3}$

                      = $\frac{8.6}{28}$

amount of $NH_{4} NO_{3}$=$\frac{8.6}{28}X 98= 30.1$

Answer 2

Answer:

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