How much amount of charge is present in 250 gm water
Answers
Answered by
0
Answer:
Mass of water= 250g
Molecular weight= 18g
No. Of moles of water= 250/18 = 13.888
No. Of moles in 250g = 13.888×6.022×10^23
=8.36×10^24
No. Of protons in one molecule of water = 10
Charge on one proton = 1.6×10^-19 C
Total +ve charge = 10×1.6×10^-19×8.36×10^24
=1.338×10^7 C (ans)
Explanation:
I know this because I am in physics plz mark as branliest!!!
Similar questions