How much amount of CuSO4. 5H2O is required for liberation of 2.54 g I2 when titrated with KI
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+ 2KI -> Cu2SO4 + K2SO4 + I2
Moles of I2 = 2.54/254 = 0.01 therefore moles of copper sulfate = 0.02 (as the molar ratio of I2:copper sulfate is 1:2 from reaction stoichiometry). Thus, grams of copper sulfate required = 0.02 * 160 = 3.2 grams of solid copper sulfate.
Moles of I2 = 2.54/254 = 0.01 therefore moles of copper sulfate = 0.02 (as the molar ratio of I2:copper sulfate is 1:2 from reaction stoichiometry). Thus, grams of copper sulfate required = 0.02 * 160 = 3.2 grams of solid copper sulfate.
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