Question

How much amount of CuSO4
.5H2O required for
liberation of 2.54 g I2
when titrated with K

Answer 1

4.99 gm

2CuSO

4

+4KI→Cu

2

I

2

+2K

2

SO

4

+I

2

Molecular wt of CuSO

4

.5H

2

O = 249.6 g/mol

Molecular wt of I

2

= 253.8 g/mol

2 moles (500 g) of CuSO

4

.5H

2

O is required to liberate 1 mol (254 g) of I

2

Amount of CuSO

4

.5H

2

O required for 2.54 g of I

2

is

=2.54×

254

500

=5

5g CuSO

4

.5H

2

O