Question

how much amount of Na2CO3 is required to form two molar solution in 1000ml​

Answer 1

Answer:

How do I find the amount of Na2CO3 required to prepare 100 ml of 0.5 molarity sodium carbonate solution?

You should add 5.299 grams of Sodium Bicarbonate in the 100 ml of solvent

you can calculate it using molarity relation

molarity = No. of moles / Liter of solution

Here, you have concentration , volume and molecular mass of Sodium bicarbonate

M = 0.1 , Vol= 0.100 Ltrs , lets assume number of moles = x (remember the units should be in same unit system)

substituting in above formula stated

we got x = 0.05 , now we need 0.05 molecules of sodium bicarbonate to be added in 100 ml so

now change the number of moles to grams

as we know 1 mole of Na2CO3 have molecular mass = 105.98

hence 0.05 moles will be = 0.05 x 105.98 = 5.299 grams