Chemistry, asked by saniaaltaf365, 1 month ago

how much amount of NaOh
is required to prepare 100 ml of 1 normal solution ​

Answers

Answered by DARKIMPERIAL
4

Answer:

To make 1N NaOH solution = dissolve 40 grams of NaOH in 1L of water. To make 0.1N NaOH solution = dissolve 40 grams of NaOH in 1L of water. For 100 ml of water = (4/1000) × 100 = 0.4 g of NaOH. Thus, the amount of NaOH required to prepare 100ml of 0.1N NaOH solution is 0.4 g of NaOH.

Explanation:

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Answered by BrainIyKohinoor
0

Answer:

Given:

Na = 23 g

O = 16 g

H = 1 g

To make 1N NaOH solution = dissolve 40 grams of NaOH in 1L of water.

To make 0.1N NaOH solution = dissolve 40 grams of NaOH in 1L of water.

To make 0.1N NaOH solution in 100 ml of water:

1000 ml of water = 4 g of NaOH

1 ml of water = (4/1000) g of NaOH

For 100 ml of water = (4/1000) × 100 = 0.4 g of NaOH.

Thus, the amount of NaOH required to prepare 100ml of 0.1N NaOH solution is 0.4 g of NaOH.

Explanation:

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