Question

how much amount of water can be decomposed through electrolysis by passing 2F charge​

Answer 1

Reaction during electrolysis of water is:

$2H_{2}O\rightarrow 2H_{2}+O_{2}$

• 1 mole of $O_{2}$ contains 4 equivalents of of $O_{2}$, and as per the law of equivalence, the number of equivalents of different substances in the balanced reaction will be equal.

According to Faraday's Law:

No. of equivalents = No. of Faradays of electricity

• Now, to decompose 2 moles of water, we need 4 Faraday of current.

So, with 2 Faraday of electricity, we can decompose (2/4 × 2) = 1 mole of water.

So, weight of water decomposed

$= 1 \: mole \times 18 \: g { \: mol}^{ - 1}$

$= 18 \: g$

So 18 grams of water is decomposed.