How much amount of water should be added to increase the pH of a solution from 1 to 2
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Explanation: Let the Initial pH = 1, i.e. [H+] = 0.1 mole/litre
Let the New pH = 2, i.e. [H+] = 0.01 mole/litre
So, In case of dilution: M1V1= M2V2
Therefore ; 0.1 ×1 =0.01 × V2
=>V2= 10 litre.
The Volume of water added = 9 litre.
Hope it helps….
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