Chemistry, asked by Bharatkaushik5510, 1 year ago

How much atoms are present in 1 gram of gold?

Answers

Answered by Anonymous
2
Hola there,

Number of moles of gold in 1g = given mass/atomic mass

= 1 / 196.96 

= 0.0050moles.

Number of atoms of gold in 1 mole of gold = Avogadro number = 6.023×10²³

So,

Number of atoms in 0.0050 moles = 6.023×10²³ × 0.0050
 = 3.057×10²¹atoms.

Therefore, 1g of gold has approximately 3.057×10²¹

Hope this helps...:)
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