How much BaCl2, would be needed to make 250 ml of a solution having same concentration of Cl as the one containing 2.92 g of NaCl per 100 ml? [1 molar BaCl2 = 2 molar CI ions]
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Answers
Answer:
Two solution of same concentration would mean that the molarity of both the solutions is equal. Therefore, first we need to calculate the molarity of NaCl solution.
Mass of NaCl = 2.92
Molar Mass of NaCl = 58.5 g/mol
Volume of NaCl Solution = 100 mL = (100 / 1000) L
(Molarity)NaCl = Mass of NaCl in grams / (Molar Mass of NaClxVolume of solution in L)
(Molarity)NaCl = (2.92 x 1000) / (58.5 x 100)
(Molarity)NaCl = 0.49mol/L
Now, (Molarity)NaCl = (Molarity)BaCl2
Mass of BaCl2 = m g
Molar Mass of BaCl2 = 208.33 g/mol
Volume of BaCl2 solution = 250 mL = (250 / 1000) L
(Molarity)BaCl2 = Mass of BaCl2 in grams/(Molar Mass of BaCl2xVolume of solution in L)
0.65 = (m x 1000) / ( 208.33 x 250) g
m = (0.49 x 208.33) / 4 g
m= 25.52g
Hence, 25.52 g of BaCl2 is required to make 250 ml of solution having same concentration of chloride as one containing 2.92 NaCl per 100ml.
Answer:
concentration same means molarity of both sol. is same wrt cl- ions
2×g/208×250]bacl2=2.92/58.5×100)NaCl
g=292×27/585
g=13.477grams