How much below the earth's surface of the earth does the acceleration due to gravity become 1% of its value at the earth's surface ?
Answer-6336km
take Radius of earth 6400 km
Answers
Answered by
47
g° = 1% of g = g/100
g°=g×[1 - d/ R]
g/100= g[1 - d/ R]
d/R = 1- 1/100
d = 99/100×6400
d = 6336Km
g°=g×[1 - d/ R]
g/100= g[1 - d/ R]
d/R = 1- 1/100
d = 99/100×6400
d = 6336Km
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Answered by
4
The answer is 6336 km
GIVEN
Acceleration due to Gravity = 1% of its value at the Earth's surface
TO FIND
Distance below the earth.
SOLUTION
We can simply solve the above problem as follows;
Let the new acceleration due to gravity = g'
ATQ,
g' = 1% of g (Where, g = acceleration due to gravity near the surface of earth)
g' = g/100
We can also write it as,
g' = g (1 - d/R)
Where,
d = distance below the Earth
R = Radius of Earth = 6400 km
Putting the value of g' as g/100
d/R = 1-1/100
d/R = 99/100
d = (99/100)× 6400
d = 99 × 6400 = 6336 km
Hence, The answer is 6336 km
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