Question

How much below the surface of earth does g reduces by 36%of its value on surface of earth?

Answer 1

We know that variation of g with depth ‘d’ is given as

g’ = g (1-(d/R)) (this is the first equation)

where g’ is the new acceleration due to gravity

d is the depth

and R is the radius

So if we say that new acceleration due to gravity is reduced to 36% that means

g’ = (36/100)g

Now substituting this value in the first equation we get

(36/100)g = g (1-(d/R))

so we have

36/100 = 1- (d/R)

simplifying we get………………….

d(depth) = R (1–0.36)

Putting the value of R and solving we get that the depth should be at

4096km