Question

How much below the surface of the earth does the acceleration due to gravity becomes 70% of its value at the surface of earth?

Answer 1

ve^2=2RM/R WHERE ve=escape speed , R = radius of earth , M = mass of earth , G = universal G constant


Vo^2=GM/R WHERE Vo=orbital speed , R = radius of earth , M = mass of earth , G = universal G constant




Ve=(2^1/2 )Vo