Physics, asked by zeba57, 11 months ago

How much boiling water at 100 degree celsius is needed to melt 2kg of ice so that the mixture which is all water is at 0 degree celsius.
Heat capacity of water-4.2 J/kg/K.
Specific latent heat of ice-336 J/g

Answers

Answered by abhi178
9

Given : m kg of boiling water at 100°C is needed to melt 2 kg of ice so that the mixture which is all water is at 0°C.

Heat capacity of water = 4200 J/Kg/K

specific latent heat of ice = 336 J/g

To find : The amount of boiling water.

solution : heat required to melt, H₁ = 2 kg × 336 J/g

= 6.72 × 10^5 Joule

heat required to increase the temperature of molten ice, H₂ = ms∆T

= m × 4200 J/Kg/K × (100°C - 0°C)

= 4.2 m × 10^5 J

from Calorimetry,

heat lost = heat gained

⇒4.2 m × 10^5 = 6.72 × 10^5

⇒m = 6.72/4.2 = 1.6 kg

Therefore amount of boiling water is 1.6 kg needed to melt 2kg of ice so that the mixture which is all water is at 0°C.

Answered by cafatia2005
1

Answer:

1.6 kg

Explanation:

The heat required to melt H₁ = 2 kg × 336 J/g

= 6.72 × 10^5 Joule

The heat required to increase the temperature of molten ice, H₂ = ms∆T

= m × 4200 J/Kg/K × (100°C - 0°C)

= 4.2 m × 10^5 J

From Calorimetry,                            (heat lost = heat gained )

⇒4.2 m × 10^5 = 6.72 × 10^5

⇒m = 6.72/4.2 = 1.6 kg

The answer is 1.6 kg

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