Question

how much CaCO3 can produce 66g of caron dioxide by reacting with excess HCL? [Ca=40 C=12 O=16] (give reaction)​

Answer 1

Your answer:

The overall reaction = CaCO₃ + 2HCl →  CaCl₂ + CO₂ + H₂O

Molar mass of CaCO₃ = 100g/mol

Molar mass of CO₂ = 44g

1 mole of  CaCO₃ gives 1 mole of CO₂

One mole of CO₂ weighs 44g and 66g of CO₂ has: 66/44 = 1.5 moles

Since one mole of CaCO₃ gives one mole of CO₂

1.5 moles of CaCO₃ gives 1.5 moles of CO₂

One mole of CaCO₃ weighs 100g

1.5 moles of CaCO₃ will weigh: 1.5 x 100 = 150 g

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